assignmentssolution@gmail.com

Get Assignments and Projects prepared by experts at a very nominal fee.

More than 8 years in assisting assignments and projects/dissertation/thesis of MBA,BBA,BCA,MCA,PhD and others-

Contact us at : Email : assignmentssolution@gmail.com

Help for : SMU, IIBM,IMT, NMIMS, NIBM ,KSBM, KAIZAN, ISBM, SYMBIOSIS, NIMS, IGNOU, XAVIER, XIBMS, ISM, PSBM, NSBM, NIRM, ISBM, ISMRC, ICMIND, UPES and many others.

Help in : Assignments, projects, M.Phil,Ph.D disseration & thesis,case studies

Courses,MBA,BBA,PhD,MPhil,EMBA,MIB,DMS,MMS,BMS,GDS etc

Contact us at : Email : assignmentssolution@gmail.com



Tuesday, 1 November 2016

AIMA Assignments: contact us for answers at assignmentssolution@gmail.com

IS07

                                                          Database Management

(For CNM Cases)
                                                                    Assignment – II
Assignment Code: 2016IS07A2                                                 Last Date of Submission: 30th April 2016
                                                                                               Maximum Marks: 100
Attempt all the questions. All the questions are compulsory and carry equal marks.
                                                                          Section-A

1.         What is normalization? Explain the advantages of normalization. Explain the first normal                           Form (1NF), second normal form (2NF) and the third normal form (3NF) with an example. 

2.         What do you understand by Database Design? Differentiate between Physical and Logical           Design.

3.         Explain Database Management Life Cycle taking an example.

4.         Write short note on:

            a.         Object Oriented Database
            b.         Data Warehousing

Section-B
Case Study
Assume you are given the following relations:
      
            Take(StudentID, CourseID)
            RequiredForGraduation(CourseID)                                                                    

The Take relation lists IDs of students and IDs of courses taken by the students. The RequiredForGraduation relation lists the courses every student must take to graduate. The following division query finds the students who have satisfied all the requirements for graduation.

SELECT StudentID
FROM Take AS T, RequiredForGraduation AS R
WHERE T.CourseID = R.CourseID
GROUP BY T.StudentID
HAVING COUNT(T.CourseID) = (SELECT COUNT(CourseID) FROM RequiredForGraduation);

Case Questions:

5.         You have an allergy to the HAVING clause. Rewrite this query without using the HAVING clause.                                                                      


No comments:

Post a Comment